广州荔湾蜜蜡批发市场:(x*x*x-x*x+x)/(x*x*x+1)+(x*x+x+1)/[(1-x*x)/x)]

来源：百度文库 编辑：查人人中国名人网 时间：2024/07/05 16:05:55

因式分解得
原式
=[x(x^2-x+1)]/[(x+1)(x^2-x+1)]+[x(x^2+x+1)]/[(x+1)(x-1)]
=x/(x+1)+[x(x^2+x+1)]/[(x+1)(x-1)]
=[x(x-1)]/(x+1)+[x(x^2+x+1)]/[(x+1)(x-1)]
=[x(x-1)+x(x^2+x+1)]/[(x+1)(x-1)]
=[x(x^2+2x)]/[(x+1)(x-1)]
=[x^2(x+2)]/[(x+1)(x-1)]

(x*x*x-x*x+x)/(x*x*x+1)+(x*x+x+1)/[(1-x*x)/x)] (x*x*x-x*x+x)/(x*x*x+1)+(x*x+x+1)/[(1-x*x)/x)] 分解因式 x.x.x.x+16-16x.x 已知x*x-3x+1=0，求x*x+1/x*x 4x？2x？ cosX=X,?X x++与++x 解一元二次方程X*X+1/X*X+X+1/X=0 解方程式3x*x*x+x*x=2 因式分解:x*x*x+2*x*x-16=0