枣庄brt10:m^2-4n^2+4n-1
来源:百度文库 编辑:查人人中国名人网 时间:2024/10/05 06:56:23
因式分解
m^2-4n^2+4n-1
=m^2-(4n^2-4n+1)
=m^2-(2n-1)^2
=(m+2n-1)(m-2n+1)
原式=m^2-(2n -1)^2=(m+2n-1)(m-2n+1)
(m+2n-1)(m-2n+1)
(m-n)2(n-m)3(n-m)4
已知|m+5|+(n-1)^100=0,求(m-7n)(9m+3n)+(4m-n)(9n-2m)
m^2-4n^2+4n-1
"1^n+2^n+3^n......+m^n=?
1^n+2^n+3^n......+m^n=
n/(n-2)+n/(n-3)+n/(n-4)+n/(n-5)+...+2/(-1)=?
(m+2n)(m+2n)=4mn求m,n的值.在线等待
已知m,n是实数,且满足4m^2+9n^2-4m+6n+2=0,那么分式(18n^2+24n+4)/(4m^2+4m-1)的值是?
(n+2)^2-n^2=4*(n+1)
解方程组:⑴3m(m-3)=2×m×m+m(m-2)-n-10 ⑵m(m+n-2)=n(m-1)+m(m+2)-4