魔兽世界所有副本资料:x+a%3*(int)(x+y)%2/4的运算顺序是怎么样的,x=2.5,a=7,y=4.7那么结果是多少
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x+a%3*(int)(x+y)%2/4的运算顺序是怎么样的,x=2.5,a=7,y=4.7那么结果是多少]
C语言
经程序验证,答案是2。5。。求正确解答!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!经程序验证,答案是2。5。。求正确解答!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!经程序验证,答案是2。5。。求正确解答!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
C语言
经程序验证,答案是2。5。。求正确解答!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!经程序验证,答案是2。5。。求正确解答!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!经程序验证,答案是2。5。。求正确解答!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
按优先级算,先括号里的,x+y=7.2,取整数=7,就是x+a%3*7%2/4,因为%*/3个优先级相同,从左往右算2.5+7%3*7%2/4=2.5+1*7%2/4=2.5+7%2/4=2.5+1/4=2.5+0=2.5
还要看你输出以什么格式,如果是%d整数格式那就是2,如果是%f浮点数那就是2.5
int a=2,b=3; float x=3.5,y=2.5; (float) (a+b)/2+(int)x%(int)y怎么算?
a=2,b=3,x=3.5,y=2.5,求(float)(a+b)/2+(int)x/(int)y的值?
x+a%3*(int)(x+y)%2/4的运算顺序是怎么样的,x=2.5,a=7,y=4.7那么结果是多少
(float)(a+b)/2+(int)x%(int)y的值为多少?
为什么x=2.5,a=7,y=4.7; s= a%3*(int)(x+y)%2/4;最后结果是0
#define MAX(x,y) (x)>(y)?(x):(y) main(){int a=5,b=2,c=3,d=3,t;t=MAX(a+b,c+d)*10;printf("%d\n",t);}
(1) x=2.5,a=7,y=4.7,求x+a%3*(int)(x+y)/24的值?
1。真心感谢大家对我的帮助,谢谢。求下面表达式的值。x+a%3*(int)(x+y)%2/4=( )
3,y=x^2+2x+3a^2
下列式子不能用平方差计算公式算的是A(x-y-z)(-x+y+z) B(-2x+3y)(3y+2x) C(x+y+z)(x-y+z) D(-5-X)(X-5